10y^2+34=284

Solution for 10y^2+34=284 equation:

10y^2+34=284

We move all terms to the left:

10y^2+34-(284)=0

We add all the numbers together, and all the variables

10y^2-250=0

a = 10; b = 0; c = -250;
Δ = b2-4ac
Δ = 02-4·10·(-250)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*10}=\frac{-100}{20}
=-5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*10}=\frac{100}{20}
=5
$